![]() Like whatever term we're on, we're multiplying by one half, Fourth term, we multiplyīy one half three times. Third term, we multiplyīy one half two times. The second term, we multiplyīy one half one time. ![]() Gonna multiply by one half? The first term, we multiplyīy one half zero times. So, we could view the exponentĪs the number of times we multiply by one half. Well, one way to thinkĪbout it is we start at 168, and then we're gonna multiply by one half, we're gonna multiply by one If I say G of N equals, think of a functionĭefinition that describes what we've just seen here starting at 168, and then multiplyingīy one half every time you add a new term. Of N, how can we define this explicitly in terms of N? And I encourage you to pause the video and think about how to do that. ![]() Times, it's often called the common ratio, times one half. We're starting at a termĪnd every successive term is the previous term And then to go from 84 to 42, you multiply by one half again. Say we subtract at 84, but another way to think about it is you multiply it by one half. If we think of it as starting at 168, and how do we go from 168 to 84? Well, one way, you could The first term is 168, second term is 84, third term is 42, and fourth term is 21,Īnd we keep going on, and on, and on. Say this is the same thing as the sequence where ![]() It is that this function, G, defines a sequence where N Show the first 4 terms, and then find the 8 th term.Ħ0. Is it possible for a sequence to be both arithmetic and geometric? If so, give an example.- So, this table here where you're given a bunch of Ns, N equals one, two, three, four, and we get the corresponding G of N. Use the explicit formula to write a geometric sequence whose common ratio is a decimal number between 0 and 1. Show the first four terms, and then find the 10 th term.ĥ9. first have a non-integer value?ĥ8. Use the recursive formula to write a geometric sequence whose common ratio is an integer. Key Equations recursive formula for nth term of a geometric sequence Multiplying any term of the sequence by the common ratio 6 generates the subsequent term. The sequence below is an example of a geometric sequence because each term increases by a constant factor of 6. Each term of a geometric sequence increases or decreases by a constant factor called the common ratio. The yearly salary values described form a geometric sequence because they change by a constant factor each year. In this section, we will review sequences that grow in this way. When a salary increases by a constant rate each year, the salary grows by a constant factor. His salary will be $26,520 after one year $27,050.40 after two years $27,591.41 after three years and so on. His annual salary in any given year can be found by multiplying his salary from the previous year by 102%. He is promised a 2% cost of living increase each year. Suppose, for example, a recent college graduate finds a position as a sales manager earning an annual salary of $26,000. Many jobs offer an annual cost-of-living increase to keep salaries consistent with inflation. Use an explicit formula for a geometric sequence.Use a recursive formula for a geometric sequence.List the terms of a geometric sequence.Find the common ratio for a geometric sequence.By the end of this section, you will be able to:
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